Hi,
I want to output today's date in one of the output column in a sequential file. The output format is mm/dd/yyyy. I am trying this .OConv(@DATE,'D/YMD[2,2,4]'). But it is not working..can anyone help me out.
Thanks
Date conversion
Moderators: chulett, rschirm, roy
Re: Date conversion
oconv(@date,"D/MDY[2,2,4]") gives output as 06/12/2008