Is there a way to attain job required parameters from a Unix shell script? I know I can get some job information using:
Job_Info=`dsjob -jobinfo DSProject DSJob`
Status code = 0
Job Status : NOT RUNNING (99)
etc...
But this does not show that the job requires two parameters when called, I.E. file_name1, file_name2
Thank you for any advice
Attaining job required parameters from a Unix shell script
Moderators: chulett, rschirm, roy
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Actually, -lparams was what I desired:
Job_Params=`dsjob -lparams DSProject DSJob`
Status code = 0
file_name1
file_name2
Thank you for your help Craig. You set me on the right path!
Job_Params=`dsjob -lparams DSProject DSJob`
Status code = 0
file_name1
file_name2
Thank you for your help Craig. You set me on the right path!
Last edited by charles.craig@physiciansm on Mon Jun 27, 2005 3:29 pm, edited 1 time in total.
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I like your recent headline Craig
How about:chulett wrote:"Apathy Sweeping Nation, No One Cares"
"I joined the team and was met with ignorance and apathy." Well, what are you going to do about it? "I don't know and I don't care."
Re: I like your recent headline Craig
charles.craig@physiciansm wrote:"I joined the team and was met with ignorance and apathy." Well, what are you going to do about it? "I don't know and I don't care."
Sorry for the wrong answer, at least (as you said) I got you pointed in the right direction.
-craig
"You can never have too many knives" -- Logan Nine Fingers
"You can never have too many knives" -- Logan Nine Fingers