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Error of excute job in command line interface
Posted: Tue Nov 08, 2005 2:08 am
by shiipip
Hi,all
When I excute "./dsjob -run -param Path=/tmp/ testprj test" in command line interface,I get the following error message:
Error -1006?Path getting information for parameter ''
Status code = -1006?
Does anyone know what's the problem?
Thanks.
Posted: Tue Nov 08, 2005 2:20 am
by loveojha2
Posted: Tue Nov 08, 2005 4:31 am
by rkdatastage
Hi
Do not specify the path to the project,
but only the project name itself is enough.
DataStage knows where the project is located and doesn't need a fully qualified path. So just execute the command:
dsjob -jobinfo <project name> <jobname>
this will work
Regards
RK
Posted: Tue Nov 08, 2005 4:39 am
by ray.wurlod
Try it without the trailing slash in the pathname.
Code: Select all
./dsjob -run -param Path=/tmp testprj test
I take it that the job does have a parameter called "Path"? Case and spelling are important.
Posted: Tue Nov 08, 2005 7:06 pm
by shiipip
I also tried this code:
./dsjob -run -param Path=/tmp testprj test
And I get the same error message.
The parameter's name is correct.
What's the meaning of "Error -1006?"?
Thanks.
Posted: Tue Nov 08, 2005 7:07 pm
by kcbland
Try it with supplying the server, userid and password options.
Posted: Wed Nov 09, 2005 2:36 am
by ray.wurlod
Code -1006 means that the project name can not be found. Check that it is spelled correctly and cased correctly.
Can you use the non-run options with dsjob? For example
Code: Select all
dsjob -jobinfo <projname> <jobname>
Posted: Thu Nov 10, 2005 2:32 am
by shiipip
To: Kenneth Bland
What's the syntax of dsjob with supplying the server, userid and password options? I execute the command just on the DataStage server. Why should I use server, userid and password options?
To: Ray Wurlod
After I executed this command "./dsjob -jobinfo testprj test",the result is correct and status code is zero. If I executed this job without paramemter options,the job finished without error.
Thank you very much.
