DSXchange

i want to populate the 16 digit incremental number for one column.
column datatype is varchar
how to generate the 16 digit number in the datastage

anyone please help me.
Thanks in advance

if its OK to have left padded 0's then use surrogate key stage and convert the output to Number(16) datatype and then map it to varchar as required.

To expand, generate regular integers, then transform them to strings with a function such as For improved performance, initialize a stage variable, say sv16zeroes, to Str("0", 16), and use the stage variable rather than the function call in the derivation expression. That way the Str() function is only evaluated once. You could use "0000000000000000" instead.

ray.wurlod wrote:To expand, generate regular integers, then transform them to strings with a function such as

Code: Select all

Right(Str("0",16):InLink.MyInteger, 16)

For improved performa ...

thanks for your reply
let me check.