About routines

[dodda]

Hi All,

Can you please tell me How to call from one Routine to another Routine..



Thanks in Advance,

[ray.wurlod]

There is nothing special about parallel routines - they are regular C++ functions. So is the calling mechanism.

[dodda]

Please let me know the syntax..
I am writing routine in BASIC language.
While calling one routine from another routine i have used "call (....)" for ex..
i have a routine A. I want to call this A in routine B. Where as A is having arguments (jobname,stagename,input1,input2 and output).
i m calling this routine like ans= call A(arguments)
but is showing error messages..
pls let me know do i need to include any header files while coding.

Thanks in advance

[OddJob]

If you have a routine called...
CallMe(Arg1)

You can call this from anther routine by using:
CALL DSU.CallMe(Ans,Arg1)

Ans is the return from CallMe. You need to add DSU. to the routine name to fully qualify it.

It's not possible to use Ans=CALL DSU.CallMe(Arg1). Using CALL to call a function, the first param is the return value (this is passed by reference).

Hope this is of help.

[kcbland]

You're confusing Functions with Routines. You declare external Functions using the DEFFUN statement, search the forum for that syntax. Then the Function can be used inline anywhere within your current Function or Routine. We CALL Routines and they don't need any declaration, just note that it has a DSU. prefix to the name you supply.

[ray.wurlod]

If you are writing routines in DataStage BASIC why did you post in the parallel forum?

[dodda]

Thanks OddJob

If you have a routine called...
CallMe(Arg1)

You can call this from anther routine by using:
CALL DSU.CallMe(Ans,Arg1)

Ans is the return from CallMe. You need to add DSU. to the routine name to fully qualify it.

It's not possible to use Ans=CALL DSU.CallMe(Arg1). Using CALL to call a function, the first param is the return value (this is passed by reference).

Hope this is of help.