command prompt error on dsjob -run

[kavuri]

Hi,
I am tried running a job from designer and viewed in director without any errors and I got output also. Here I am using a job parameter which I had created a new one.
But when I am trying to run the same from command prompt I am getting the following error.

$ dsjob -run -mode NORMAL custdev gender_code_lookup -param '$sourcefilepath=/home/bhi/fix-csv/gender_code_lookup.csv'
Invalid arguments: dsjob -run
[-mode <NORMAL | RESET | VALIDATE>]
[-param <name>=<value>]
[-warn <n>]
[-rows <n>]
[-wait]
[-opmetadata <TRUE | FALSE>]
[-disableprjhandler]
[-disablejobhandler]
[-jobstatus]
[-userstatus]
[-local]
[-useid]
<project> <job|jobid>

Status code = -9999 DSJE_DSJOB_ERROR


I name d the parameter as "sourcefilepath" and prompt as "path". I tried all combinations with and without $ and both with path and sourcefilepath but unable to get the result.

Plz let me know whats the error is.

Thanks
Kavuri

[chulett]

Note the difference in the usage statement generated by your error and the way you are calling dsjob. The Project and Job Name must be the last two entries on the command line.

[mohdsuf]

Your command is :
$ dsjob -run -mode NORMAL custdev gender_code_lookup -param '$sourcefilepath=/home/bhi/fix-csv/gender_code_lookup.csv'


Change it like this as :
$ dsjob -run -mode NORMAL custdev gender_code_lookup -param sourcefilepath=/home/bhi/fix-csv/gender_code_lookup.csv
(removing $ sign and single quotes)

Try this and do let us know.

[mohdsuf]

Also make a little modification in it:
$ dsjob -run -mode NORMAL custdev gender_code_lookup -param sourcefilepath=/home/bhi/fix-csv/gender_code_lookup.csv <project_name> <job_name>