avoid the Return Code for dsjob command in shell script

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pratapsriram
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avoid the Return Code for dsjob command in shell script

Post by pratapsriram »

I am trying to get the start time for a given job by running this command in a shell script.

Code: Select all

JOB_STARTDATE=`${BinFileDirectory}/dsjob -jobinfo $PROJECT $DSJOB|grep 'Job Start Time'|cut -d":" -f2`
echo $JOB_STARTDATE
The output is
Status code = 0
Mon Apr 25 10
How do I avoid gettting the
Status code = 0
in my result?
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