function for extcting the middle part of the field
Moderators: chulett, rschirm, roy
-
- Premium Member
- Posts: 315
- Joined: Tue Oct 31, 2006 3:38 pm
function for extcting the middle part of the field
which function to use in the transformer to get for example the characters from 16 to 22 in the field of 86 length?
-
- Participant
- Posts: 54607
- Joined: Wed Oct 23, 2002 10:52 pm
- Location: Sydney, Australia
- Contact:
Therefore
Code: Select all
InLink.FieldName[16,7]
IBM Software Services Group
Any contribution to this forum is my own opinion and does not necessarily reflect any position that IBM may hold.
Any contribution to this forum is my own opinion and does not necessarily reflect any position that IBM may hold.