How to trap the exit status code value of a dsjob command ?

[kumarjit]

I went through numerous posts and I wasnt able to find that one piece of GOLD which can bail me out of this misery.

The scenario is : I am executing the "dsjob" command from our Unix prompt(using a shell script) and passing the same project name and job name to it , and the differences being in the usage of the following options of the command .
a) -mode
b) -jobstatus
i.e., once I am executing the dsjob command with these options, and once I am not using them.

What is required : To store the status of the dsjob command(and not the status of the datastage job) , i.e., the staus code returned by the dsjob command to the OS


Whats the problem :
While using the Unix command " echo $? " right after executing the dsjob command , I am a value of 0 when the dsjob command runs SUCCESSFULLY without its options,
and 1 when the dsjob command runs SUCCESSFULLY with the options used alongwith (mentioned above ) .

Question :
IF THE DSJOB COMMAND RUNS SUCCESSFULLY , IT WOULD ONLY RETURN 0 AS THE STATUS CODE , NO MATTER WHAT OPTIONS ARE USED ALONGWITH THE COMMAND ITSELF. BUT ITS NOT HAPPENING THAT WAY .

CAN ANY BODY HELP ME OUT WITH THIS ISSUE ?


Thanks
Kumarjit.

[chulett]

You don't want -jobstatus as that reflects the value the job returned. You should be able to use -wait for a simple 0/1 return status, assuming you want to wait for the job to complete, that is.