constraint in transformer

[India2000]

Hi,

I have a constraint in the transformer

X=1 and Y=1 and @False

this evaluates to zero and nothing pass thro the transformer.

What is the use of @False in this expression when it should be @true to evaluate the condition to true and pass values to the output.

Can anyone clarify me wit this ?


Thanks

[meet_deb85]

Why are you using @True as a constraint, the compiler replaces @True with 1 and @False with 0.

[BI-RMA]

As meet_deb85 pointed out correctly, @False is just a more 'visible' way of expressing 0 as a boolean.

In your expression you do not compare @False to anything. So the last condition will never become true and as a result the whole expression will always turn out to be false. You will need to specify which condition has to be false to make the expression as a whole true.

[chulett]

What is the use of @False in this expression

I'm guessing someone added it (as part of their debugging / bottleneck investigation) to shut down that link... and then forgot to remove it later. Or are still investigating. Or that link no longer needs to ever send rows down it and they wanted to preserve the original constraint.

In my world, there would be an annotation explaining that or something would be written in one of the General property areas that support that same concept - documentation!


Note to OP: moved my answer over from your other copy of this same question to here and deleted the duplicate post. Please do not post the same question in multiple forums! And this one is getting moved to the General forum.

[qt_ky]

Your contstraint is the same as @False alone. You don't need to add @True or @False to any constraint. Just leave it as X=1 And Y=1.

[chulett]

Before you change anything, you need to understand why it is there.