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if then else problem
Posted: Fri Jun 15, 2007 12:53 am
by seshikumar
hi guys,
i have code like this aruments i dec arg1,a1,a2
if arg1= '+' then
res=a1+a2
else
if arg1='-' then
res=a1+a2
else
if arg1='*' then
res=a1*a2
end
end
end
when i was compiling the code iam getting error
Re: if then else problem
Posted: Fri Jun 15, 2007 1:11 am
by srinath
seshikumar wrote:hi guys,
i have code like this aruments i dec arg1,a1,a2
if arg1= '+' then
res=a1+a2
else
if arg1='-' then
res=a1+a2
else
if arg1='*' then
res=a1*a2
end
end
end
when i was compiling the code iam getting error
if Arg1= '+' or Arg1='-' then
res=a1+a2
end
else if Arg1='*' then
res=a1*a2
end
Posted: Fri Jun 15, 2007 1:55 am
by JKenklies
I think you need an else clause at the end because the compiler needs to be sure, that in every situation you'll get some result.
What if arg1="crap"?
Saying your variable is called "someValue", the following example should work (delete the comments):
Code: Select all
if arg1= '+' then
res=a1+a2
else
if arg1='-' then
res=a1-a2 // I bet this was a typo?
else
if arg1='*' then
res=a1*a2
else
someValue // this will be returned if arg1 not in (+,-,*)
Re: if then else problem
Posted: Fri Jun 15, 2007 2:03 am
by JeroenDmt
you need to add two extra 'end' statements before the 'else'
So it will be
Code: Select all
if arg1= '+' then
res=a1+a2
end
else
if arg1='-' then
res=a1+a2
end
else
if arg1='*' then
res=a1*a2
end
end
end
Then it compiles correctly.
Posted: Fri Jun 15, 2007 2:26 am
by ray.wurlod
Is this in a routine or in a derivation expression? Your answer to that will affect what is the correct answer to your question.
Please delete duplicate post.
Re: if then else problem
Posted: Fri Jun 15, 2007 2:33 am
by JoshGeorge
res = a1 arg1 a2
If my assumption below is right.
seshikumar wrote:hi guys,
i have code like this aruments i dec arg1,a1,a2
if arg1= '+' then
res=a1+a2
else
if arg1='-' then
<b> res=a1-a2 </b> **** Assuming this is a typo --> res=a1+a2
else
if arg1='*' then
res=a1*a2
end
end
end
when i was compiling the code iam getting error
THis is routine
Posted: Fri Jun 15, 2007 2:45 am
by seshikumar
ray.wurlod wrote:Is this in a routine or in a derivation expression? Your answer to that will affect what is the correct answer to your question.
Please delete duplicate post.
Posted: Fri Jun 15, 2007 3:00 pm
by ray.wurlod
Is this in a routine or in a derivation expression? Your answer to that will affect what is the correct answer to your question.
