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How to remove carriage retrun from the last line of a file
Posted: Fri Sep 01, 2006 6:54 am
by reddy
Sir,
I am concatenating 3 files using exec command stage like this
copy D:\Sequential_Files\CREATEHEADER + D:\Sequential_Files\CREATEDETAIL + D:\Sequential_Files\CREATETRAILER D:\Sequential_Files\BAH_HR_yyyymmdd.txt
but at the end of D:\Sequential_Files\BAH_HR_yyyymmdd.txt file i am
getting carriage return/line feed terminator.
Can you please help me out on how to remove line terminator.
Thanks
Reddy
Posted: Fri Sep 01, 2006 6:57 am
by ArndW
Does you windows installation have MKS Toolkit or other unix command emulation installed? If so, you can use the commands "wc -l" and "head" to remove the last line from a file. If not, you can always write a DS job to perform the same functionality.
Posted: Fri Sep 01, 2006 7:45 am
by ray.wurlod
Why bother? If you are going to process all of this, simply add a constraint early in the job that skips that final empty line. Set your "missing field" properties appropriately.
Posted: Fri Sep 01, 2006 8:09 am
by reddy
Thanks for quick respond.
Once i combined all 3 files i am sending this file to user but they are telling they are getting problems with line feed terminator.
because of small file i am deleting manually last line.
can you help me on how to remove last line in windows.
Thanks
Narasa
Posted: Fri Sep 01, 2006 8:23 am
by ArndW
Narasa, did my previous suggestion not work?
Posted: Fri Sep 01, 2006 11:12 am
by katz
Hi reddy,
I am not able to recreate your output exactly, but with the COPY command I do get a non-printable character of hex(1A) as the last character of the file.
I don't get this character if I use the /B option (binary file copy) with the COPY command. For example,
Code: Select all
COPY /B file1.txt + file2.txt + file3.txt fileout.txt
produces an output file with no extra characters at the end. Perhaps you can test the /B option.
katz