DSXchange

Hi all,

i have a list of data which is look like that -> 07:30 ,12:30,09:30
what i have to do is i have to extract the data from 07:30 -> 07 , 12:30 ->
12, 09:30 ->09
I used the Oconv(data field name , "G:1") then i can get the 07,12,09

But i dunno how to make it from 07 -> 7 ,12 ->12 , 09 ->9
is there anyway to disappear the zero infront when the data have a zero infront?

please help
thank you

Performing any arithmetic operation in a DataStage BASIC expression, such as adding zero to the number, will strip non-significant leading and trailing zeroes.

You might also investigate the Field() function, which is slightly more efficient that the group conversion you have chosen to do.

ray.wurlod wrote:
Performing any arithmetic operation in a DataStage BASIC expression, such as adding zero to the number, will strip non-significant l ...

Hi,

Eventhough i cant see half of ur explaination....i forgot the trim function.
I'm now using the trim(xxx,0,'L') but still thinking of the field data which is 0:00 -> i have to maintain the 0 to them if the data is 0:00......


anyway thank a lot!

chowmunyee wrote:

ray.wurlod wrote:
Performing any arithmetic operation in a DataStage BASIC expression, such as adding zero to the number, will strip non-significant l ...

Hi,

Eventhough i cant see half of ur explaination....i forgot the trim function.
I'm now using the trim(xxx,0,'L') but still thinking of the field data which is 0:00 -> i have to maintain the 0 to them if the data is 0:00......


anyway thank a lot!

I have think of the idea to solve is using if else statement. I'm not sure this is the best or worst but at least i can able to achieved the expected result. Please share with me if you have the better solution than mine one...

I'm using
if trim(oconv(xxx, G:1),0,'L')=\\
Then '0'
Else trim(oconv(xxx, G:1),0,'L')

Thank you

As Ray has already stated, just add a 0 to the number in a derivation and your leading zeroes will be stripped out.