need help -- dsjob -run

[sravanthi]

Hi,

I have a batch script to call a sequencer.It is like :

cd \Ascential\DataStage\Engine\bin
dsjob -run -warn 0 DS-PRJ sequencer

This job has dependency job which should run after this job.

Does this script exits immediately or after successful completion of job.Please let me know

[chulett]

Without one of the 'wait' options on the command line, it will fall squarely into your "exits immediately" camp.

[sravanthi]

Thanks Craig

How to add that wait to this script.What is command for that.please advice!

[sravanthi]

Thanks Craig

How to add that wait to this script.What is command for that.please advice!

[chulett]

It's all documented in the Server Job Developer's Guide in the Command Line Inteface chapter. Use either "-wait" or "-jobstatus" depending on how you want the exit status handled.

[sravanthi]

Craig,

I have modified to dsjob -run -warn 0 -wait DS-PRJ sequencer

Is this enough or do we need some thing else.

[chulett]

It's enough as long as you understand the difference between "-wait" and "-jobstatus". Did you read the documentation?

[sravanthi]

I did.Wait ...waits for job to complete.

jobstatus waits for job to complete and gives an exit code from job status.Hope it returns 1 which is not complete for other process except data stage.

Not sure how to use jobstatus which returns 0 to indicate job is completed.

[chulett]

-wait returns 'normal' exit status codes: 0 for success, non-zero for failure. -jobstatus returns the same code as used internally: 1 = Finished OK, 2 = Finished (see log), 3 = Aborted, etc etc.

[sravanthi]

Thanks