dsjob (status code)

[DSguru2B]

That is the job return code. When you stick in "-jobstatus" to your dsjob command, the status code will be the job return code. When you execute the dsjob command without the "-jobstatus", the command exit code will be returned.

[mystuff]

Great Thanks for the help

[mystuff]

Code: Select all

eval dsjob -lognewest $Project $JobName | awk -F"\=" '{print $2}' | read EventId 
              if [ $? -ne 0 ] 
              then 
                  echo "Error." 
                  exit 2 
              fi 
.....Next command....... 

I still get the output Status Code=0

[mystuff]

Code: Select all

eval dsjob -lognewest $Project $JobName | awk -F"\=" '{print $2}' | read EventId 
              if [ $? -ne 0 ] 
              then 
                  echo "Error." 
                  exit 2 
              fi 
.....Next command....... 

I still get the output Status Code=0

[DSguru2B]

Thats fine, you can ignore that.
With the above code you are acomplising both, getting the event id and checking the status of your command.
The status code will still be spit out onto stdout, which is your screen. That shouldnt be of any concern, its harmless.

[ray.wurlod]

$? is the exit status of the final command in the pipeline - in your case the read command. You need different logic to have the shell script exit with the value of the dsjob exit status.

[DSguru2B]

Ray, does'nt 'eval' take care of that and treat the piped commands as a single command?